Distance from Manhattan Beach to Mercato San Severino
The shortest distance (air line) between Manhattan Beach and Mercato San Severino is 6,478.92 mi (10,426.81 km).
How far is Manhattan Beach from Mercato San Severino
Manhattan Beach is located in California, United States within 33° 53' 21.84" N -119° 36' 11.88" W (33.8894, -118.3967) coordinates. The local time in Manhattan Beach is 09:33 (03.03.2025)
Mercato San Severino is located in Salerno, Italy within 40° 46' 59.88" N 14° 46' 0.12" E (40.7833, 14.7667) coordinates. The local time in Mercato San Severino is 18:33 (03.03.2025)
The calculated flying distance from Mercato San Severino to Mercato San Severino is 6,478.92 miles which is equal to 10,426.81 km.
Manhattan Beach, California, United States
Related Distances from Manhattan Beach
Mercato San Severino, Salerno, Italy