Distance from Manhattan Beach to Sveti Ivan Zelina
The shortest distance (air line) between Manhattan Beach and Sveti Ivan Zelina is 6,236.81 mi (10,037.17 km).
How far is Manhattan Beach from Sveti Ivan Zelina
Manhattan Beach is located in California, United States within 33° 53' 21.84" N -119° 36' 11.88" W (33.8894, -118.3967) coordinates. The local time in Manhattan Beach is 09:16 (27.01.2025)
Sveti Ivan Zelina is located in Zagrebačka županija, Croatia within 45° 57' 34.56" N 16° 14' 35.16" E (45.9596, 16.2431) coordinates. The local time in Sveti Ivan Zelina is 18:16 (27.01.2025)
The calculated flying distance from Sveti Ivan Zelina to Sveti Ivan Zelina is 6,236.81 miles which is equal to 10,037.17 km.
Manhattan Beach, California, United States
Related Distances from Manhattan Beach
Sveti Ivan Zelina, Zagrebačka županija, Croatia