Distance from Mankato to Diepenbeek
The shortest distance (air line) between Mankato and Diepenbeek is 4,294.94 mi (6,912.04 km).
How far is Mankato from Diepenbeek
Mankato is located in Minnesota, United States within 44° 10' 17.4" N -94° 1' 22.08" W (44.1715, -93.9772) coordinates. The local time in Mankato is 21:20 (02.02.2025)
Diepenbeek is located in Arr. Hasselt, Belgium within 50° 54' 25.92" N 5° 25' 3" E (50.9072, 5.4175) coordinates. The local time in Diepenbeek is 04:20 (03.02.2025)
The calculated flying distance from Diepenbeek to Diepenbeek is 4,294.94 miles which is equal to 6,912.04 km.
Mankato, Minnesota, United States
Related Distances from Mankato
Diepenbeek, Arr. Hasselt, Belgium