Distance from Maple Heights to Aleksandrow Lodzki
The shortest distance (air line) between Maple Heights and Aleksandrow Lodzki is 4,447.65 mi (7,157.80 km).
How far is Maple Heights from Aleksandrow Lodzki
Maple Heights is located in Ohio, United States within 41° 24' 33.84" N -82° 26' 15" W (41.4094, -81.5625) coordinates. The local time in Maple Heights is 09:52 (22.05.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 15:52 (22.05.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 4,447.65 miles which is equal to 7,157.80 km.
Maple Heights, Ohio, United States
Related Distances from Maple Heights
Aleksandrow Lodzki, Łódzki, Poland