Distance from Market Harborough to San Severino Marche
The shortest distance (air line) between Market Harborough and San Severino Marche is 911.07 mi (1,466.23 km).
How far is Market Harborough from San Severino Marche
Market Harborough is located in Leicestershire CC and Rutland, United Kingdom within 52° 28' 39" N -1° 4' 45.84" W (52.4775, -0.9206) coordinates. The local time in Market Harborough is 00:44 (16.12.2025)
San Severino Marche is located in Macerata, Italy within 43° 13' 44.04" N 13° 10' 37.56" E (43.2289, 13.1771) coordinates. The local time in San Severino Marche is 01:44 (16.12.2025)
The calculated flying distance from San Severino Marche to San Severino Marche is 911.07 miles which is equal to 1,466.23 km.
Market Harborough, Leicestershire CC and Rutland, United Kingdom
Related Distances from Market Harborough
San Severino Marche, Macerata, Italy