Distance from Martinsburg to Clermont-Ferrand
The shortest distance (air line) between Martinsburg and Clermont-Ferrand is 3,964.17 mi (6,379.72 km).
How far is Martinsburg from Clermont-Ferrand
Martinsburg is located in West Virginia, United States within 39° 27' 29.52" N -78° 1' 20.64" W (39.4582, -77.9776) coordinates. The local time in Martinsburg is 03:19 (08.12.2025)
Clermont-Ferrand is located in Puy-de-Dôme, France within 45° 46' 59.16" N 3° 4' 56.64" E (45.7831, 3.0824) coordinates. The local time in Clermont-Ferrand is 09:19 (08.12.2025)
The calculated flying distance from Clermont-Ferrand to Clermont-Ferrand is 3,964.17 miles which is equal to 6,379.72 km.
Martinsburg, West Virginia, United States
Related Distances from Martinsburg
Clermont-Ferrand, Puy-de-Dôme, France