Distance from Martinsburg to Diepenbeek
The shortest distance (air line) between Martinsburg and Diepenbeek is 3,916.56 mi (6,303.10 km).
How far is Martinsburg from Diepenbeek
Martinsburg is located in West Virginia, United States within 39° 27' 29.52" N -78° 1' 20.64" W (39.4582, -77.9776) coordinates. The local time in Martinsburg is 08:43 (04.04.2025)
Diepenbeek is located in Arr. Hasselt, Belgium within 50° 54' 25.92" N 5° 25' 3" E (50.9072, 5.4175) coordinates. The local time in Diepenbeek is 14:43 (04.04.2025)
The calculated flying distance from Diepenbeek to Diepenbeek is 3,916.56 miles which is equal to 6,303.10 km.
Martinsburg, West Virginia, United States
Related Distances from Martinsburg
Diepenbeek, Arr. Hasselt, Belgium