Distance from Martinsburg to Koekelberg
The shortest distance (air line) between Martinsburg and Koekelberg is 3,874.18 mi (6,234.90 km).
How far is Martinsburg from Koekelberg
Martinsburg is located in West Virginia, United States within 39° 27' 29.52" N -78° 1' 20.64" W (39.4582, -77.9776) coordinates. The local time in Martinsburg is 12:37 (18.04.2025)
Koekelberg is located in Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium within 50° 52' 0.12" N 4° 19' 59.88" E (50.8667, 4.3333) coordinates. The local time in Koekelberg is 18:37 (18.04.2025)
The calculated flying distance from Koekelberg to Koekelberg is 3,874.18 miles which is equal to 6,234.90 km.
Martinsburg, West Virginia, United States
Related Distances from Martinsburg
Koekelberg, Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium