Distance from Martinsburg to Septemes-les-Vallons
The shortest distance (air line) between Martinsburg and Septemes-les-Vallons is 4,137.96 mi (6,659.40 km).
How far is Martinsburg from Septemes-les-Vallons
Martinsburg is located in West Virginia, United States within 39° 27' 29.52" N -78° 1' 20.64" W (39.4582, -77.9776) coordinates. The local time in Martinsburg is 04:51 (16.12.2025)
Septemes-les-Vallons is located in Bouches-du-Rhône, France within 43° 23' 53.88" N 5° 21' 56.88" E (43.3983, 5.3658) coordinates. The local time in Septemes-les-Vallons is 10:51 (16.12.2025)
The calculated flying distance from Septemes-les-Vallons to Septemes-les-Vallons is 4,137.96 miles which is equal to 6,659.40 km.
Martinsburg, West Virginia, United States
Related Distances from Martinsburg
Septemes-les-Vallons, Bouches-du-Rhône, France