Distance from Martinsburg to Sint-Andries
The shortest distance (air line) between Martinsburg and Sint-Andries is 3,819.22 mi (6,146.43 km).
How far is Martinsburg from Sint-Andries
Martinsburg is located in West Virginia, United States within 39° 27' 29.52" N -78° 1' 20.64" W (39.4582, -77.9776) coordinates. The local time in Martinsburg is 13:44 (13.01.2026)
Sint-Andries is located in Arr. Brugge, Belgium within 51° 12' 0" N 3° 10' 59.88" E (51.2000, 3.1833) coordinates. The local time in Sint-Andries is 19:44 (13.01.2026)
The calculated flying distance from Sint-Andries to Sint-Andries is 3,819.22 miles which is equal to 6,146.43 km.
Martinsburg, West Virginia, United States
Related Distances from Martinsburg
Sint-Andries, Arr. Brugge, Belgium