Distance from Martinsville to Bad Sooden-Allendorf
The shortest distance (air line) between Martinsville and Bad Sooden-Allendorf is 4,292.86 mi (6,908.69 km).
How far is Martinsville from Bad Sooden-Allendorf
Martinsville is located in Virginia, United States within 36° 40' 57.36" N -80° 8' 11.04" W (36.6826, -79.8636) coordinates. The local time in Martinsville is 14:09 (26.02.2025)
Bad Sooden-Allendorf is located in Werra-Meißner-Kreis, Germany within 51° 16' 59.88" N 9° 58' 59.88" E (51.2833, 9.9833) coordinates. The local time in Bad Sooden-Allendorf is 20:09 (26.02.2025)
The calculated flying distance from Bad Sooden-Allendorf to Bad Sooden-Allendorf is 4,292.86 miles which is equal to 6,908.69 km.
Martinsville, Virginia, United States
Related Distances from Martinsville
Bad Sooden-Allendorf, Werra-Meißner-Kreis, Germany