Distance from Martinsville to Begijnendijk
The shortest distance (air line) between Martinsville and Begijnendijk is 4,093.17 mi (6,587.32 km).
How far is Martinsville from Begijnendijk
Martinsville is located in Virginia, United States within 36° 40' 57.36" N -80° 8' 11.04" W (36.6826, -79.8636) coordinates. The local time in Martinsville is 08:30 (13.02.2025)
Begijnendijk is located in Arr. Leuven, Belgium within 51° 1' 6.96" N 4° 47' 6" E (51.0186, 4.7850) coordinates. The local time in Begijnendijk is 14:30 (13.02.2025)
The calculated flying distance from Begijnendijk to Begijnendijk is 4,093.17 miles which is equal to 6,587.32 km.
Martinsville, Virginia, United States
Related Distances from Martinsville
Begijnendijk, Arr. Leuven, Belgium