Distance from Martinsville to Buggenhout
The shortest distance (air line) between Martinsville and Buggenhout is 4,069.98 mi (6,550.00 km).
How far is Martinsville from Buggenhout
Martinsville is located in Virginia, United States within 36° 40' 57.36" N -80° 8' 11.04" W (36.6826, -79.8636) coordinates. The local time in Martinsville is 11:21 (10.02.2025)
Buggenhout is located in Arr. Dendermonde, Belgium within 51° 0' 0" N 4° 12' 0" E (51.0000, 4.2000) coordinates. The local time in Buggenhout is 17:21 (10.02.2025)
The calculated flying distance from Buggenhout to Buggenhout is 4,069.98 miles which is equal to 6,550.00 km.
Martinsville, Virginia, United States
Related Distances from Martinsville
Buggenhout, Arr. Dendermonde, Belgium