Distance from Martinsville to Diepenbeek
The shortest distance (air line) between Martinsville and Diepenbeek is 4,121.58 mi (6,633.04 km).
How far is Martinsville from Diepenbeek
Martinsville is located in Virginia, United States within 36° 40' 57.36" N -80° 8' 11.04" W (36.6826, -79.8636) coordinates. The local time in Martinsville is 21:01 (10.02.2025)
Diepenbeek is located in Arr. Hasselt, Belgium within 50° 54' 25.92" N 5° 25' 3" E (50.9072, 5.4175) coordinates. The local time in Diepenbeek is 03:01 (11.02.2025)
The calculated flying distance from Diepenbeek to Diepenbeek is 4,121.58 miles which is equal to 6,633.04 km.
Martinsville, Virginia, United States
Related Distances from Martinsville
Diepenbeek, Arr. Hasselt, Belgium