Distance from Martinsville to Koekelberg
The shortest distance (air line) between Martinsville and Koekelberg is 4,078.75 mi (6,564.11 km).
How far is Martinsville from Koekelberg
Martinsville is located in Virginia, United States within 36° 40' 57.36" N -80° 8' 11.04" W (36.6826, -79.8636) coordinates. The local time in Martinsville is 02:07 (14.02.2025)
Koekelberg is located in Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium within 50° 52' 0.12" N 4° 19' 59.88" E (50.8667, 4.3333) coordinates. The local time in Koekelberg is 08:07 (14.02.2025)
The calculated flying distance from Koekelberg to Koekelberg is 4,078.75 miles which is equal to 6,564.11 km.
Martinsville, Virginia, United States
Related Distances from Martinsville
Koekelberg, Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium