Distance from Martinsville to Steenokkerzeel
The shortest distance (air line) between Martinsville and Steenokkerzeel is 4,084.52 mi (6,573.40 km).
How far is Martinsville from Steenokkerzeel
Martinsville is located in Virginia, United States within 36° 40' 57.36" N -80° 8' 11.04" W (36.6826, -79.8636) coordinates. The local time in Martinsville is 16:14 (11.02.2025)
Steenokkerzeel is located in Arr. Halle-Vilvoorde, Belgium within 50° 55' 8.04" N 4° 30' 29.88" E (50.9189, 4.5083) coordinates. The local time in Steenokkerzeel is 22:14 (11.02.2025)
The calculated flying distance from Steenokkerzeel to Steenokkerzeel is 4,084.52 miles which is equal to 6,573.40 km.
Martinsville, Virginia, United States
Related Distances from Martinsville
Steenokkerzeel, Arr. Halle-Vilvoorde, Belgium