Distance from Meriden to Aleksandrow Kujawski
The shortest distance (air line) between Meriden and Aleksandrow Kujawski is 4,067.51 mi (6,546.03 km).
How far is Meriden from Aleksandrow Kujawski
Meriden is located in Connecticut, United States within 41° 32' 12.84" N -73° 12' 19.44" W (41.5369, -72.7946) coordinates. The local time in Meriden is 11:04 (14.03.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 17:04 (14.03.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 4,067.51 miles which is equal to 6,546.03 km.
Meriden, Connecticut, United States
Related Distances from Meriden
Aleksandrow Kujawski, Włocławski, Poland