Distance from Minot to Mercato San Severino
The shortest distance (air line) between Minot and Mercato San Severino is 5,153.37 mi (8,293.55 km).
How far is Minot from Mercato San Severino
Minot is located in North Dakota, United States within 48° 14' 15" N -102° 43' 19.2" W (48.2375, -101.2780) coordinates. The local time in Minot is 09:32 (14.03.2025)
Mercato San Severino is located in Salerno, Italy within 40° 46' 59.88" N 14° 46' 0.12" E (40.7833, 14.7667) coordinates. The local time in Mercato San Severino is 16:32 (14.03.2025)
The calculated flying distance from Mercato San Severino to Mercato San Severino is 5,153.37 miles which is equal to 8,293.55 km.
Minot, North Dakota, United States
Related Distances from Minot
Mercato San Severino, Salerno, Italy