Distance from Mint Hill to Asenovgrad
The shortest distance (air line) between Mint Hill and Asenovgrad is 5,327.52 mi (8,573.82 km).
How far is Mint Hill from Asenovgrad
Mint Hill is located in North Carolina, United States within 35° 10' 41.88" N -81° 20' 49.92" W (35.1783, -80.6528) coordinates. The local time in Mint Hill is 02:44 (25.02.2025)
Asenovgrad is located in Plovdiv, Bulgaria within 42° 1' 0.12" N 24° 52' 0.12" E (42.0167, 24.8667) coordinates. The local time in Asenovgrad is 09:44 (25.02.2025)
The calculated flying distance from Asenovgrad to Asenovgrad is 5,327.52 miles which is equal to 8,573.82 km.
Mint Hill, North Carolina, United States