Distance from Monte San Savino to Aleksandrow Kujawski
The shortest distance (air line) between Monte San Savino and Aleksandrow Kujawski is 732.61 mi (1,179.02 km).
How far is Monte San Savino from Aleksandrow Kujawski
Monte San Savino is located in Arezzo, Italy within 43° 19' 59.88" N 11° 43' 59.88" E (43.3333, 11.7333) coordinates. The local time in Monte San Savino is 00:00 (11.03.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 00:00 (11.03.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 732.61 miles which is equal to 1,179.02 km.
Monte San Savino, Arezzo, Italy
Related Distances from Monte San Savino
Aleksandrow Kujawski, Włocławski, Poland