Distance from Monte San Savino to Boynton Beach
The shortest distance (air line) between Monte San Savino and Boynton Beach is 5,070.59 mi (8,160.33 km).
How far is Monte San Savino from Boynton Beach
Monte San Savino is located in Arezzo, Italy within 43° 19' 59.88" N 11° 43' 59.88" E (43.3333, 11.7333) coordinates. The local time in Monte San Savino is 19:08 (11.12.2025)
Boynton Beach is located in Florida, United States within 26° 31' 41.16" N -81° 55' 8.04" W (26.5281, -80.0811) coordinates. The local time in Boynton Beach is 13:08 (11.12.2025)
The calculated flying distance from Boynton Beach to Boynton Beach is 5,070.59 miles which is equal to 8,160.33 km.
Monte San Savino, Arezzo, Italy
Related Distances from Monte San Savino
Boynton Beach, Florida, United States