Distance from Montechiarugolo to Aleksandrow Lodzki
The shortest distance (air line) between Montechiarugolo and Aleksandrow Lodzki is 638.85 mi (1,028.13 km).
How far is Montechiarugolo from Aleksandrow Lodzki
Montechiarugolo is located in Parma, Italy within 44° 41' 36.24" N 10° 25' 20.64" E (44.6934, 10.4224) coordinates. The local time in Montechiarugolo is 16:05 (25.05.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 16:05 (25.05.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 638.85 miles which is equal to 1,028.13 km.
Related Distances from Montechiarugolo
Aleksandrow Lodzki, Łódzki, Poland