Distance from Montechiarugolo to Alexandroupoli
The shortest distance (air line) between Montechiarugolo and Alexandroupoli is 825.57 mi (1,328.63 km).
How far is Montechiarugolo from Alexandroupoli
Montechiarugolo is located in Parma, Italy within 44° 41' 36.24" N 10° 25' 20.64" E (44.6934, 10.4224) coordinates. The local time in Montechiarugolo is 03:03 (10.05.2025)
Alexandroupoli is located in Evros, Greece within 40° 51' 0" N 25° 52' 0.12" E (40.8500, 25.8667) coordinates. The local time in Alexandroupoli is 04:03 (10.05.2025)
The calculated flying distance from Alexandroupoli to Alexandroupoli is 825.57 miles which is equal to 1,328.63 km.