Distance from Montechiarugolo to Drobeta-Turnu Severin
The shortest distance (air line) between Montechiarugolo and Drobeta-Turnu Severin is 600.35 mi (966.16 km).
How far is Montechiarugolo from Drobeta-Turnu Severin
Montechiarugolo is located in Parma, Italy within 44° 41' 36.24" N 10° 25' 20.64" E (44.6934, 10.4224) coordinates. The local time in Montechiarugolo is 02:05 (08.06.2025)
Drobeta-Turnu Severin is located in Mehedinţi, Romania within 44° 37' 59.88" N 22° 38' 60" E (44.6333, 22.6500) coordinates. The local time in Drobeta-Turnu Severin is 03:05 (08.06.2025)
The calculated flying distance from Drobeta-Turnu Severin to Drobeta-Turnu Severin is 600.35 miles which is equal to 966.16 km.
Related Distances from Montechiarugolo
Drobeta-Turnu Severin, Mehedinţi, Romania