Distance from Montechiarugolo to Mercato San Severino
The shortest distance (air line) between Montechiarugolo and Mercato San Severino is 348.58 mi (560.99 km).
How far is Montechiarugolo from Mercato San Severino
Montechiarugolo is located in Parma, Italy within 44° 41' 36.24" N 10° 25' 20.64" E (44.6934, 10.4224) coordinates. The local time in Montechiarugolo is 18:01 (28.05.2025)
Mercato San Severino is located in Salerno, Italy within 40° 46' 59.88" N 14° 46' 0.12" E (40.7833, 14.7667) coordinates. The local time in Mercato San Severino is 18:01 (28.05.2025)
The calculated flying distance from Mercato San Severino to Mercato San Severino is 348.58 miles which is equal to 560.99 km.
Related Distances from Montechiarugolo
Mercato San Severino, Salerno, Italy