Distance from Moorestown-Lenola to Sint-Andries
The shortest distance (air line) between Moorestown-Lenola and Sint-Andries is 3,674.73 mi (5,913.91 km).
How far is Moorestown-Lenola from Sint-Andries
Moorestown-Lenola is located in New Jersey, United States within 39° 57' 57.24" N -75° 2' 8.52" W (39.9659, -74.9643) coordinates. The local time in Moorestown-Lenola is 04:03 (05.02.2025)
Sint-Andries is located in Arr. Brugge, Belgium within 51° 12' 0" N 3° 10' 59.88" E (51.2000, 3.1833) coordinates. The local time in Sint-Andries is 10:03 (05.02.2025)
The calculated flying distance from Sint-Andries to Sint-Andries is 3,674.73 miles which is equal to 5,913.91 km.
Moorestown-Lenola, New Jersey, United States
Related Distances from Moorestown-Lenola
Sint-Andries, Arr. Brugge, Belgium