Distance from Morgantown to Le Kremlin-Bicetre
The shortest distance (air line) between Morgantown and Le Kremlin-Bicetre is 3,922.53 mi (6,312.70 km).
How far is Morgantown from Le Kremlin-Bicetre
Morgantown is located in West Virginia, United States within 39° 38' 17.88" N -80° 3' 12.96" W (39.6383, -79.9464) coordinates. The local time in Morgantown is 18:11 (07.02.2025)
Le Kremlin-Bicetre is located in Val-de-Marne, France within 48° 48' 36" N 2° 21' 29.16" E (48.8100, 2.3581) coordinates. The local time in Le Kremlin-Bicetre is 00:11 (08.02.2025)
The calculated flying distance from Le Kremlin-Bicetre to Le Kremlin-Bicetre is 3,922.53 miles which is equal to 6,312.70 km.
Morgantown, West Virginia, United States
Related Distances from Morgantown
Le Kremlin-Bicetre, Val-de-Marne, France