Distance from New Albany to Montceau-les-Mines
The shortest distance (air line) between New Albany and Montceau-les-Mines is 4,374.60 mi (7,040.24 km).
How far is New Albany from Montceau-les-Mines
New Albany is located in Indiana, United States within 38° 18' 32.4" N -86° 10' 35.76" W (38.3090, -85.8234) coordinates. The local time in New Albany is 08:45 (11.02.2025)
Montceau-les-Mines is located in Saône-et-Loire, France within 46° 40' 0.84" N 4° 22' 8.04" E (46.6669, 4.3689) coordinates. The local time in Montceau-les-Mines is 14:45 (11.02.2025)
The calculated flying distance from Montceau-les-Mines to Montceau-les-Mines is 4,374.60 miles which is equal to 7,040.24 km.
New Albany, Indiana, United States
Related Distances from New Albany
Montceau-les-Mines, Saône-et-Loire, France