Distance from Newport News to Aleksandrow Kujawski
The shortest distance (air line) between Newport News and Aleksandrow Kujawski is 4,426.72 mi (7,124.12 km).
How far is Newport News from Aleksandrow Kujawski
Newport News is located in Virginia, United States within 37° 6' 18.36" N -77° 28' 53.4" W (37.1051, -76.5185) coordinates. The local time in Newport News is 05:04 (01.03.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 11:04 (01.03.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 4,426.72 miles which is equal to 7,124.12 km.
Newport News, Virginia, United States
Related Distances from Newport News
Aleksandrow Kujawski, Włocławski, Poland