Distance from Oakley to Cesky Tesin
The shortest distance (air line) between Oakley and Cesky Tesin is 5,909.86 mi (9,511.00 km).
How far is Oakley from Cesky Tesin
Oakley is located in California, United States within 37° 59' 34.44" N -122° 18' 17.28" W (37.9929, -121.6952) coordinates. The local time in Oakley is 09:46 (11.02.2025)
Cesky Tesin is located in Moravskoslezský kraj, Czechia within 49° 44' 45.96" N 18° 37' 33.96" E (49.7461, 18.6261) coordinates. The local time in Cesky Tesin is 18:46 (11.02.2025)
The calculated flying distance from Cesky Tesin to Cesky Tesin is 5,909.86 miles which is equal to 9,511.00 km.
Oakley, California, United States
Related Distances from Oakley
Cesky Tesin, Moravskoslezský kraj, Czechia