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      Distance from Oakley to Saint-Andre-les-Vergers

      The shortest distance (air line) between Oakley and Saint-Andre-les-Vergers is 5,610.14 mi (9,028.65 km).

      How far is Oakley from Saint-Andre-les-Vergers

      Oakley is located in California, United States within 37° 59' 34.44" N -122° 18' 17.28" W (37.9929, -121.6952) coordinates. The local time in Oakley is 15:56 (22.02.2025)

      Saint-Andre-les-Vergers is located in Aube, France within 48° 16' 46.92" N 4° 3' 14.04" E (48.2797, 4.0539) coordinates. The local time in Saint-Andre-les-Vergers is 00:56 (23.02.2025)

      The calculated flying distance from Saint-Andre-les-Vergers to Saint-Andre-les-Vergers is 5,610.14 miles which is equal to 9,028.65 km.

      Oakley, California, United States

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      Saint-Andre-les-Vergers, Aube, France

      Related Distances to Saint-Andre-les-Vergers