Distance from Oakley to San Lazzaro di Savena
The shortest distance (air line) between Oakley and San Lazzaro di Savena is 6,032.35 mi (9,708.13 km).
How far is Oakley from San Lazzaro di Savena
Oakley is located in California, United States within 37° 59' 34.44" N -122° 18' 17.28" W (37.9929, -121.6952) coordinates. The local time in Oakley is 16:28 (06.03.2025)
San Lazzaro di Savena is located in Bologna, Italy within 44° 28' 17.76" N 11° 24' 17.64" E (44.4716, 11.4049) coordinates. The local time in San Lazzaro di Savena is 01:28 (07.03.2025)
The calculated flying distance from San Lazzaro di Savena to San Lazzaro di Savena is 6,032.35 miles which is equal to 9,708.13 km.
Oakley, California, United States
Related Distances from Oakley
San Lazzaro di Savena, Bologna, Italy