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      Distance from Oakley to San Pancrazio Salentino

      The shortest distance (air line) between Oakley and San Pancrazio Salentino is 6,445.55 mi (10,373.11 km).

      How far is Oakley from San Pancrazio Salentino

      Oakley is located in California, United States within 37° 59' 34.44" N -122° 18' 17.28" W (37.9929, -121.6952) coordinates. The local time in Oakley is 16:06 (06.03.2025)

      San Pancrazio Salentino is located in Brindisi, Italy within 40° 25' 0.12" N 17° 49' 59.88" E (40.4167, 17.8333) coordinates. The local time in San Pancrazio Salentino is 01:06 (07.03.2025)

      The calculated flying distance from San Pancrazio Salentino to San Pancrazio Salentino is 6,445.55 miles which is equal to 10,373.11 km.

      Oakley, California, United States

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      San Pancrazio Salentino, Brindisi, Italy

      Related Distances to San Pancrazio Salentino