Distance from Oakley to Sint Anthonis
The shortest distance (air line) between Oakley and Sint Anthonis is 5,484.85 mi (8,827.02 km).
How far is Oakley from Sint Anthonis
Oakley is located in California, United States within 37° 59' 34.44" N -122° 18' 17.28" W (37.9929, -121.6952) coordinates. The local time in Oakley is 05:13 (12.03.2025)
Sint Anthonis is located in Noordoost-Noord-Brabant, Netherlands within 51° 37' 32.88" N 5° 52' 51.96" E (51.6258, 5.8811) coordinates. The local time in Sint Anthonis is 14:13 (12.03.2025)
The calculated flying distance from Sint Anthonis to Sint Anthonis is 5,484.85 miles which is equal to 8,827.02 km.
Oakley, California, United States
Related Distances from Oakley
Sint Anthonis, Noordoost-Noord-Brabant, Netherlands