Distance from Oakley to Sint-Pieters-Leeuw
The shortest distance (air line) between Oakley and Sint-Pieters-Leeuw is 5,484.11 mi (8,825.82 km).
How far is Oakley from Sint-Pieters-Leeuw
Oakley is located in California, United States within 37° 59' 34.44" N -122° 18' 17.28" W (37.9929, -121.6952) coordinates. The local time in Oakley is 16:28 (09.02.2025)
Sint-Pieters-Leeuw is located in Arr. Halle-Vilvoorde, Belgium within 50° 46' 59.88" N 4° 15' 0" E (50.7833, 4.2500) coordinates. The local time in Sint-Pieters-Leeuw is 01:28 (10.02.2025)
The calculated flying distance from Sint-Pieters-Leeuw to Sint-Pieters-Leeuw is 5,484.11 miles which is equal to 8,825.82 km.
Oakley, California, United States
Related Distances from Oakley
Sint-Pieters-Leeuw, Arr. Halle-Vilvoorde, Belgium