Distance from Oakley to Sveti Ivan Zelina
The shortest distance (air line) between Oakley and Sveti Ivan Zelina is 6,076.80 mi (9,779.67 km).
How far is Oakley from Sveti Ivan Zelina
Oakley is located in California, United States within 37° 59' 34.44" N -122° 18' 17.28" W (37.9929, -121.6952) coordinates. The local time in Oakley is 12:01 (14.02.2025)
Sveti Ivan Zelina is located in Zagrebačka županija, Croatia within 45° 57' 34.56" N 16° 14' 35.16" E (45.9596, 16.2431) coordinates. The local time in Sveti Ivan Zelina is 21:01 (14.02.2025)
The calculated flying distance from Sveti Ivan Zelina to Sveti Ivan Zelina is 6,076.80 miles which is equal to 9,779.67 km.
Oakley, California, United States
Related Distances from Oakley
Sveti Ivan Zelina, Zagrebačka županija, Croatia