Distance from Odorheiu Secuiesc to Leavenworth
The shortest distance (air line) between Odorheiu Secuiesc and Leavenworth is 5,464.56 mi (8,794.35 km).
How far is Odorheiu Secuiesc from Leavenworth
Odorheiu Secuiesc is located in Harghita, Romania within 46° 18' 50.04" N 25° 18' 6.12" E (46.3139, 25.3017) coordinates. The local time in Odorheiu Secuiesc is 16:12 (04.01.2026)
Leavenworth is located in Kansas, United States within 39° 19' 26.04" N -95° 4' 33.6" W (39.3239, -94.9240) coordinates. The local time in Leavenworth is 08:12 (04.01.2026)
The calculated flying distance from Leavenworth to Leavenworth is 5,464.56 miles which is equal to 8,794.35 km.
Odorheiu Secuiesc, Harghita, Romania
Related Distances from Odorheiu Secuiesc
Leavenworth, Kansas, United States