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      Distance from Oerlinghausen to San Pancrazio Salentino

      The shortest distance (air line) between Oerlinghausen and San Pancrazio Salentino is 908.89 mi (1,462.72 km).

      How far is Oerlinghausen from San Pancrazio Salentino

      Oerlinghausen is located in Lippe, Germany within 51° 58' 0.12" N 8° 40' 0.12" E (51.9667, 8.6667) coordinates. The local time in Oerlinghausen is 03:40 (01.03.2025)

      San Pancrazio Salentino is located in Brindisi, Italy within 40° 25' 0.12" N 17° 49' 59.88" E (40.4167, 17.8333) coordinates. The local time in San Pancrazio Salentino is 03:40 (01.03.2025)

      The calculated flying distance from San Pancrazio Salentino to San Pancrazio Salentino is 908.89 miles which is equal to 1,462.72 km.

      Oerlinghausen, Lippe, Germany

      Related Distances from Oerlinghausen

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      Oerlinghausen to Duisburg89.44 mi (143.94 km)
      Oerlinghausen to Dusseldorf95.40 mi (153.53 km)
      Oerlinghausen to Cologne102.53 mi (165.01 km)
      Oerlinghausen to Bonn108.78 mi (175.06 km)
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      Oerlinghausen to Wiesbaden131.50 mi (211.63 km)
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      Oerlinghausen to Mannheim171.50 mi (276.00 km)
      Oerlinghausen to Nuremberg203.12 mi (326.89 km)
      Oerlinghausen to Berlin204.03 mi (328.36 km)
      Oerlinghausen to Karlsruhe204.67 mi (329.38 km)
      Oerlinghausen to Stuttgart221.51 mi (356.48 km)
      Oerlinghausen to Dresden227.12 mi (365.52 km)
      Oerlinghausen to Augsburg267.44 mi (430.41 km)
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      San Pancrazio Salentino, Brindisi, Italy

      Related Distances to San Pancrazio Salentino