Distance from Oisterwijk to Seymour
The shortest distance (air line) between Oisterwijk and Seymour is 4,221.43 mi (6,793.73 km).
How far is Oisterwijk from Seymour
Oisterwijk is located in Midden-Noord-Brabant, Netherlands within 51° 34' 59.88" N 5° 12' 0" E (51.5833, 5.2000) coordinates. The local time in Oisterwijk is 22:04 (12.03.2025)
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 16:04 (12.03.2025)
The calculated flying distance from Seymour to Seymour is 4,221.43 miles which is equal to 6,793.73 km.
Oisterwijk, Midden-Noord-Brabant, Netherlands
Related Distances from Oisterwijk
Seymour, Indiana, United States