Distance from Old Jamestown to Montceau-les-Mines
The shortest distance (air line) between Old Jamestown and Montceau-les-Mines is 4,533.84 mi (7,296.51 km).
How far is Old Jamestown from Montceau-les-Mines
Old Jamestown is located in Missouri, United States within 38° 50' 21.84" N -91° 42' 55.08" W (38.8394, -90.2847) coordinates. The local time in Old Jamestown is 15:51 (05.06.2025)
Montceau-les-Mines is located in Saône-et-Loire, France within 46° 40' 0.84" N 4° 22' 8.04" E (46.6669, 4.3689) coordinates. The local time in Montceau-les-Mines is 22:51 (05.06.2025)
The calculated flying distance from Montceau-les-Mines to Montceau-les-Mines is 4,533.84 miles which is equal to 7,296.51 km.
Old Jamestown, Missouri, United States
Related Distances from Old Jamestown
Montceau-les-Mines, Saône-et-Loire, France