Distance from Oldenburg in Holstein to Alexandroupoli
The shortest distance (air line) between Oldenburg in Holstein and Alexandroupoli is 1,157.39 mi (1,862.64 km).
How far is Oldenburg in Holstein from Alexandroupoli
Oldenburg in Holstein is located in Ostholstein, Germany within 54° 17' 60" N 10° 52' 59.88" E (54.3000, 10.8833) coordinates. The local time in Oldenburg in Holstein is 18:41 (28.05.2025)
Alexandroupoli is located in Evros, Greece within 40° 51' 0" N 25° 52' 0.12" E (40.8500, 25.8667) coordinates. The local time in Alexandroupoli is 19:41 (28.05.2025)
The calculated flying distance from Alexandroupoli to Alexandroupoli is 1,157.39 miles which is equal to 1,862.64 km.
Oldenburg in Holstein, Ostholstein, Germany