Distance from Oosterhout to Dix Hills
The shortest distance (air line) between Oosterhout and Dix Hills is 3,628.58 mi (5,839.63 km).
How far is Oosterhout from Dix Hills
Oosterhout is located in West-Noord-Brabant, Netherlands within 51° 38' 35.16" N 4° 51' 24.84" E (51.6431, 4.8569) coordinates. The local time in Oosterhout is 04:11 (04.03.2025)
Dix Hills is located in New York, United States within 40° 48' 11.88" N -74° 39' 45" W (40.8033, -73.3375) coordinates. The local time in Dix Hills is 22:11 (03.03.2025)
The calculated flying distance from Dix Hills to Dix Hills is 3,628.58 miles which is equal to 5,839.63 km.
Oosterhout, West-Noord-Brabant, Netherlands
Related Distances from Oosterhout
Dix Hills, New York, United States