Distance from Orcutt to Mercato San Severino
The shortest distance (air line) between Orcutt and Mercato San Severino is 6,484.99 mi (10,436.59 km).
How far is Orcutt from Mercato San Severino
Orcutt is located in California, United States within 34° 52' 8.76" N -121° 34' 40.08" W (34.8691, -120.4222) coordinates. The local time in Orcutt is 20:12 (14.03.2025)
Mercato San Severino is located in Salerno, Italy within 40° 46' 59.88" N 14° 46' 0.12" E (40.7833, 14.7667) coordinates. The local time in Mercato San Severino is 05:12 (15.03.2025)
The calculated flying distance from Mercato San Severino to Mercato San Severino is 6,484.99 miles which is equal to 10,436.59 km.
Orcutt, California, United States
Related Distances from Orcutt
Mercato San Severino, Salerno, Italy