Distance from Orcutt to Monte San Savino
The shortest distance (air line) between Orcutt and Monte San Savino is 6,250.86 mi (10,059.79 km).
How far is Orcutt from Monte San Savino
Orcutt is located in California, United States within 34° 52' 8.76" N -121° 34' 40.08" W (34.8691, -120.4222) coordinates. The local time in Orcutt is 21:55 (14.03.2025)
Monte San Savino is located in Arezzo, Italy within 43° 19' 59.88" N 11° 43' 59.88" E (43.3333, 11.7333) coordinates. The local time in Monte San Savino is 06:55 (15.03.2025)
The calculated flying distance from Monte San Savino to Monte San Savino is 6,250.86 miles which is equal to 10,059.79 km.
Orcutt, California, United States
Related Distances from Orcutt
Monte San Savino, Arezzo, Italy