Distance from Oshkosh to Bad Sassendorf
The shortest distance (air line) between Oshkosh and Bad Sassendorf is 4,181.42 mi (6,729.34 km).
How far is Oshkosh from Bad Sassendorf
Oshkosh is located in Wisconsin, United States within 44° 1' 21.72" N -89° 26' 17.16" W (44.0227, -88.5619) coordinates. The local time in Oshkosh is 09:21 (08.02.2025)
Bad Sassendorf is located in Soest, Germany within 51° 34' 59.16" N 8° 10' 0.12" E (51.5831, 8.1667) coordinates. The local time in Bad Sassendorf is 16:21 (08.02.2025)
The calculated flying distance from Bad Sassendorf to Bad Sassendorf is 4,181.42 miles which is equal to 6,729.34 km.
Oshkosh, Wisconsin, United States
Related Distances from Oshkosh
Bad Sassendorf, Soest, Germany