Distance from Oshkosh to Saint-Genis-Pouilly
The shortest distance (air line) between Oshkosh and Saint-Genis-Pouilly is 4,316.28 mi (6,946.39 km).
How far is Oshkosh from Saint-Genis-Pouilly
Oshkosh is located in Wisconsin, United States within 44° 1' 21.72" N -89° 26' 17.16" W (44.0227, -88.5619) coordinates. The local time in Oshkosh is 05:20 (12.02.2025)
Saint-Genis-Pouilly is located in Ain, France within 46° 14' 35.88" N 6° 1' 17.04" E (46.2433, 6.0214) coordinates. The local time in Saint-Genis-Pouilly is 12:20 (12.02.2025)
The calculated flying distance from Saint-Genis-Pouilly to Saint-Genis-Pouilly is 4,316.28 miles which is equal to 6,946.39 km.
Oshkosh, Wisconsin, United States
Related Distances from Oshkosh
Saint-Genis-Pouilly, Ain, France