Distance from Oshkosh to Sveti Ivan Zelina
The shortest distance (air line) between Oshkosh and Sveti Ivan Zelina is 4,710.20 mi (7,580.33 km).
How far is Oshkosh from Sveti Ivan Zelina
Oshkosh is located in Wisconsin, United States within 44° 1' 21.72" N -89° 26' 17.16" W (44.0227, -88.5619) coordinates. The local time in Oshkosh is 10:28 (10.02.2025)
Sveti Ivan Zelina is located in Zagrebačka županija, Croatia within 45° 57' 34.56" N 16° 14' 35.16" E (45.9596, 16.2431) coordinates. The local time in Sveti Ivan Zelina is 17:28 (10.02.2025)
The calculated flying distance from Sveti Ivan Zelina to Sveti Ivan Zelina is 4,710.20 miles which is equal to 7,580.33 km.
Oshkosh, Wisconsin, United States
Related Distances from Oshkosh
Sveti Ivan Zelina, Zagrebačka županija, Croatia