Distance from Oswego to Alexandria
The shortest distance (air line) between Oswego and Alexandria is 5,234.86 mi (8,424.69 km).
How far is Oswego from Alexandria
Oswego is located in Illinois, United States within 41° 41' 0.24" N -89° 39' 46.08" W (41.6834, -88.3372) coordinates. The local time in Oswego is 12:32 (04.03.2025)
Alexandria is located in Teleorman, Romania within 43° 58' 6.96" N 25° 19' 59.88" E (43.9686, 25.3333) coordinates. The local time in Alexandria is 20:32 (04.03.2025)
The calculated flying distance from Alexandria to Alexandria is 5,234.86 miles which is equal to 8,424.69 km.
Oswego, Illinois, United States
Related Distances from Oswego
Alexandria, Teleorman, Romania