Distance from Overland Park to Sveti Ivan Zelina
The shortest distance (air line) between Overland Park and Sveti Ivan Zelina is 5,185.41 mi (8,345.12 km).
How far is Overland Park from Sveti Ivan Zelina
Overland Park is located in Kansas, United States within 38° 53' 13.2" N -95° 18' 46.8" W (38.8870, -94.6870) coordinates. The local time in Overland Park is 23:49 (04.02.2025)
Sveti Ivan Zelina is located in Zagrebačka županija, Croatia within 45° 57' 34.56" N 16° 14' 35.16" E (45.9596, 16.2431) coordinates. The local time in Sveti Ivan Zelina is 06:49 (05.02.2025)
The calculated flying distance from Sveti Ivan Zelina to Sveti Ivan Zelina is 5,185.41 miles which is equal to 8,345.12 km.
Overland Park, Kansas, United States
Related Distances from Overland Park
Sveti Ivan Zelina, Zagrebačka županija, Croatia