Distance from Oxon Hill to Begijnendijk
The shortest distance (air line) between Oxon Hill and Begijnendijk is 3,878.44 mi (6,241.74 km).
How far is Oxon Hill from Begijnendijk
Oxon Hill is located in Maryland, United States within 38° 47' 18.24" N -77° 1' 38.28" W (38.7884, -76.9727) coordinates. The local time in Oxon Hill is 00:46 (04.02.2025)
Begijnendijk is located in Arr. Leuven, Belgium within 51° 1' 6.96" N 4° 47' 6" E (51.0186, 4.7850) coordinates. The local time in Begijnendijk is 06:46 (04.02.2025)
The calculated flying distance from Begijnendijk to Begijnendijk is 3,878.44 miles which is equal to 6,241.74 km.
Oxon Hill, Maryland, United States
Related Distances from Oxon Hill
Begijnendijk, Arr. Leuven, Belgium